PHP Login
I'm trying to code a login for my site. It is an odd registration message whereby the register script send me an e-mail to check before I manually add the user to the database. I am having problems with mysql_result(). This is my login code:
<?
$user=$_POST['username'];
$pass=$_POST['password'];
$encpass=md5($pass);
$mysqluser="mastergamer";
$mysqlpass="pass hidden";
$dbase="mastergamer";
mysql_connect(localhost, $user, $pass);
@mysql_select_db($dbase) or die( "Unable to select database");
$query="SELECT * FROM `users` WHERE user='$user' and pass='$encpass'";
$result=mysql_query($query);
$returneduser=mysql_result($result, "username");
$returnedpass=mysql_result($result, "password");
$returnedmail=mysql_result($result, "email");
mysql_close();
if($user==$returneduser && $encpass==$returnedpass)
{
echo "Now logged in as $user";
} else {
echo "Login error, please try again";
}
?>
I keep getting this error:
Warning: mysql_result(): supplied argument is not a valid MySQL result resource.
What do I need to change in mysql_result() i order for it to work?
$user=$_POST['username'];
$pass=$_POST['password'];
$encpass=md5($pass);
$mysqluser="mastergamer";
$mysqlpass="pass hidden";
$dbase="mastergamer";
mysql_connect(localhost, $user, $pass);
@mysql_select_db($dbase) or die( "Unable to select database");
$query="SELECT * FROM `users` WHERE user='$user' and pass='$encpass'";
$result=mysql_query($query);
$row=mysql_fetch_array($result);
$returneduser=($row['user']);
$returnedpass=($row['pass']);
$returnedmail=($row['email']);
mysql_close();
if($user==$returneduser && $encpass==$returnedpass)
{
echo "Now logged in as $user";
} else {
echo "Login error, please try again";
}
?>
Another thought, could it be that you are using "username" rather than "user"???
I changed the code to:
<?
$user=$_POST['username'];
$pass=$_POST['password'];
$encpass=md5($pass);
$mysqluser="mastergamer";
$mysqlpass="hidden";
$dbase="mastergamer";
mysql_connect(localhost, $user, $pass);
@mysql_select_db($dbase) or die( "Unable to select database");
$query="SELECT * FROM `users` WHERE username='$user' and password='$encpass'";
$result=mysql_query($query);
$row=mysql_fetch_array($result);
$returneduser=mysql_result($row['username']);
$returnedpass=mysql_result($row['password']);
$returnedmail=mysql_result($row['email']);
mysql_close();
if($user==$returneduser && $encpass==$returnedpass)
{
echo "Now logged in as $user";
} else {
echo "Login error, please try again";
}
?>
and now it gives me the error:
markupWrong parameter count for mysql_result()
EDIT: Fixed it now, I changed $returneduser=mysql_result($row['username']); to $returneduser=mysql_result($result,0,username); and now it works.
Thanks for your help :)
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