I made an encryption code...(Not sure if I actually made it...)

I call it Bragadecima. (Bracket-Decimal)

Try and figure out how it works, and make sure that you explain how it works. I will give you a word that you need to figure out (there is a big clue in the encryption its self). There is no numbers in the word, it is just letters.

(0.09)0.16, 0.13, 0.20, 0.20, 0.10, 0.23, 0.29, 0.22, 0.12(0.09)

If you can get it please remember to explain how. Remember there is quite a big hint in the encrytion its self. PM me if you get it and tell me how there but don't explain it here just post the answer.

If you cant get that one try this one:

(0.03)0.06,0.03,0.06(0.03)

I'll give it a try, but could you encrypt a paragraph instead of a small string?

n3w7yp3 wrote: I'll give it a try, but could you encrypt a paragraph instead of a small string? Its only one word… and for a hint the brackets do nothing but enclose the word.

Hey, just saw this post.

The answer is Hellbound

ok i understand what the outside bracket represents and that each number after the decimal represents a letter but how did you get the letter H from 16 ::EDIT:: never mind i got it i can decrypt that too

ohh now i get it…

every letter has its number a = 0.00 b = 0.01 ect and the (0.09) means it just changes the 0.01 to 0.10

So h -> 0.07 + (0.09) = 0.16 e -> 0.02 + (0.09) = 0.13 l -> 0.11 + (0.09) = 0.20 l -> 0.11 + (0.09) = 0.20 b -> 0.02 + (0.09) = 0.10 o -> 0.14 + (0.09) = 0.23 u -> 0.20 + (0.09) = 0.29 n -> 0.17 + (0.09) = 0.22 d -> 0.03 + (0.09) = 0.12 _______

(0.09)0.16, 0.13, 0.20, 0.20, 0.10, 0.23, 0.29, 0.22, 0.12(0.09) == hellbound

i think

Well of course everybody can figure it out now that I've posted the answer :-P

(0.09)0.16, 0.13, 0.20, 0.20, 0.10, 0.23, 0.29, 0.22, 0.12(0.09)

so,

A=1 B=2 C=3 D=4 and so on, so :

(0.16100)-(0.09100)+1 = 08 = H (0.13100)-(0.09100)+1 = 05 = E (0.20100)-(0.09100)+1 = 12 = L (0.20100)-(0.09100)+1 = 12 = L (0.10100)-(0.09100)+1 = 02 = B (0.23100)-(0.09100)+1 = 15 = 0 (0.29100)-(0.09100)+1 = 21 = U (0.22100)-(0.09100)+1 = 14 = N (0.12100)-(0.09100)+1 = 04 = D

Edit : :( I just see the post a bit above…It sayed it before me :@…:(

Nice job jake. it's a simple cryptoquip jump anyways.

Jake wrote: Well of course everybody can figure it out now that I've posted the answer :-P

Yea lol thats what i meant by "now i get it…" :p

Good job… its pretty easy…

I really don't know how Jake just sees through encryptions so easily? :s It confuses me so much!

Haha i actually laughed when i saw that. He reads encryptions like i read plaintext

i made one as well curious to see if someone can get it(below)

Chislam hacks edited lost loving members lifes totally.

^^ is the encrypted message. Decrypt it! By the way there is a space that is not in the decrypted message but you will know the words.

The answer is 'HBH Rules'

Jake you are elite!!!lol

I will come up with a new encryption style soon… i will make a new thread for it…

ok jake try this

11010001100011111000111110011100110111111000100110010011100111101101111110010110100011111000101011011111100001111001001010011 11011010001

any one else may try and decrypt this and i will tell you that don't just think that you can solve this binary to get the anser theres something you have to do to the binary first

edit this is 100% original encryption (as far as i know) so there is nothing on the internet that will help and also no name so if any one would like to name this encrytion please do or classify it or some thx have fun