Basic 24
lesserlightsofheaven wrote: yeah, I couldn't get any commands to run.
is embarrassed
lol, why not? Admin commands is restricted, you can only use the md5, sha, etc..
- User Commands +
@help Displays this message. @say message Tells bot to say "message". @md5 string MD5's "string". @b64 string Base 64 encodes "string". @sha1 string SHA-1's "string". @rot47 string ROT-47 encodes "string". @hex string Hex encodes "string". @md5crack hash Finds the plaintext of "hash" (MD5). @b64crack encoded Finds the plaintext of "encoded" (Base 64). @sha1crack hash Finds the plaintext of "hash" (SHA-1). @rot47crack encoded Finds the plaintext of "encoded" (ROT-47). @hex2ascii ascii Finds the plaintext of "ascii" (Hex).
Doesn't appear to be working, unless it's just simulated and only one command works, I've been trying to get it to "@say hello" for a while with no luck, and if it's specific about the command you must use I'll just get bored and quit :P
Happysmileman wrote: Doesn't appear to be working, unless it's just simulated and only one command works, I've been trying to get it to "@say hello" for a while with no luck, and if it's specific about the command you must use I'll just get bored and quit :P
PM me with what you've tried so far (on here or the IRC), and I'll see what's up with it.
tried all types of commands none are working period even @help. Is this thing up or whatQQ?
Okay the level is up ..
and i joined the server but there is no channel named #basic24 !! there is no channels at all
i typed " /join #basic24 "
and i can send any command >> not as the challenge said :
Commands are prefixed with an @ sign, @help is the only command you can run inside the channel, other commands must be sent as a private message.
is this right ?!
Help :whoa:
Hey guys, just completed this challenge. Pretty tough until you realize the trick. Here are some pointers:
- We want the bot to issue a command, which means it must be done on his end not ours.
- A obvious place to start would be with the @say command, but remember we have other useful functions as well(hint hint).
- A command is issued on a single line only, and not as part of a functions output.
- Read pointer 3 again and then read pointer 2.
Hope this will help some of you solve this challenge. :)