Math Problem.
Hey guys, im stuck on some homework and i was wondering if anyone knew a proof that demonstraights the irrationality of the square root of three. The way im thinking about it is all rational numbers can be made into a fraction right?
(if someone could get me the keypad code to make a square root sign that would be sweet. i'll show how square root of 2 is proved. alt+0+?)
http://www.google.com JUST FUCKING GOOGLE IT BEFORE POSTING. Took me 7 seconds to find the answer.
i like that point placebo. i'll definatly ask about that. heres the conclusion i've come to (cus i know u all are on the edge of your seats): sqrt 3 = a fraction of intergers in simplest terms (a^2/b^2) a^2=3b^2 therefore a^2 must be divisible by 3 and 9
b^2=a^2/3 therefore b^2 is divisible by 3… which means a^2/b^2 isnt in lowest terms! which is a contradiction.